Equilibrium Problem: Solving for Unknown Masses in a Mobile

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SUMMARY

The discussion focuses on solving for unknown masses in a mobile system in equilibrium, specifically determining the masses of objects A, C, and D given that object B has a mass of 0.735 kg. Participants emphasize the application of the law of leverage, which states that the moments around the pivot must be equal for the system to remain balanced. A correction is noted regarding the distance measurement, suggesting that the distance should be 0.15m instead of 15m. This highlights the importance of accurate measurements in calculations.

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  • Understanding of the law of leverage
  • Basic principles of equilibrium in physics
  • Ability to perform calculations involving moments
  • Familiarity with mobile structures and their components
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of equilibrium and mechanics in mobile systems.

ratt10mm
.3m>>>>>| .075m
---------------
|>>>>>15m<<|>>.05m
A>>>>>>>-------------
>>.175m>>|.05m>>>>>|
>>------------>>>>>>B
>>|>>>>>>>>>|
>>D>>>>>>>>>C

( > are spaces and - are the crossbars.)
Alright pretend this is a mobile in equilibrium. I'm given that object B is .735kg and i need to determine the masses of the other ojects...
 
Last edited by a moderator:
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Hi ratt10mm,
15m looks wrong, isn't it rather .15m?

Anyway, you know the law of leverage, plus you know that B must be balanced against C+D. That's where to start, I think.
 
What the heck?[?]
 

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