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Rank 3 tensor created by taking the derivative of electromagnetic field tensor |
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| Oct19-09, 01:11 AM | #1 |
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Rank 3 tensor created by taking the derivative of electromagnetic field tensor
1. The problem statement, all variables and given/known data
Show that the rank 3 tensor [tex]S_{\alpha \beta \gamma}=F_{\alpha \beta , \gamma} + F_{\beta \gamma , \alpha} + F_{\gamma \alpha , \beta}[/tex] is completely antisymmetric. I just don't feel comfortable doing this stuff at all. Each of the three terms seems like they should be exactly the same to me. Could someone show me how I would start doing something like this please? Furthermore, if this is a rank 3 tensor, what would it mean if this tensor equals 0? Thanks. :-\ |
| Oct20-09, 03:16 AM | #2 |
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Recognitions:
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If [itex]S_{\alpha\beta\gamma}[/itex] is completely antisymmetric, then
[tex]S_{\alpha\beta\gamma}=-S_{\alpha\gamma\beta}[/tex] [tex]S_{\alpha\beta\gamma}=-S_{\beta\alpha\gamma}[/tex] and [tex]S_{\alpha\beta\gamma}=-S_{\gamma\beta\alpha}[/tex] That is, [itex]S_{\alpha\beta\gamma}[/itex] is antisymmetric on all pairs of indices.... So, start by comparing [itex]S_{\alpha\beta\gamma}[/itex] to [itex]S_{\alpha\gamma\beta}[/itex] using the definition you posted... |
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