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Velocity Height Calculation check 
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#1
Oct2509, 09:33 AM

P: 39

1. An object of mass 1.2kg is fired vertically in a barrel velocity 25n acting over a period of 0.25 seconds, calculate A) The velocity when leave the gun. B). Height reached. C). Time taken to return to initial height.
2. a= f/m, V^2=U^2+2as 3. A), A=F/M for acceleration, 25/1.2= 20.8 Velocity = V0+AT = 0+20.8x0.25=5.2m/s B). Height reached = V^2=U^2 + 2AS, 0=5.2^2 + 2 (9.81)s 0= 27  19.62 x s, S = 27 / 19.62 = 1.38m C). Time, S = (T/2( (UxV), T= 1.38 x 2/5.2 = 0.5 as require to arrive back = 2 x 0.5 = 1 Second any comments appreciated 


#2
Oct2509, 10:06 AM

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P: 6,671

In A you are not taking into account the fact that it is fired vertically. Do a free body diagram showing the forces acting, including the 25 N applied force. AM 


#3
Oct2709, 06:31 AM

P: 39

V0+at Should be V0Gt? 


#4
Oct2709, 10:20 AM

Sci Advisor
HW Helper
P: 6,671

Velocity Height Calculation check
AM 


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