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Related Rates: Man and Spotlight |
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| Nov5-09, 12:20 AM | #1 |
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Related Rates: Man and Spotlight
1. The problem statement, all variables and given/known data
A 2m tall person walks toward toward a wall at 1.6 m/s. A spotlight 12 m away from the wall shines at it. How fast is the length of his shadow on the wall decreasing when he is 4m away from the wall? I tried a few different things with trig, none of which worked. |
| Nov5-09, 12:38 AM | #2 |
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like what?
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| Nov5-09, 12:40 AM | #3 |
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Well, actually I couldn't figure out how to setup the equation to begin with.
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| Nov5-09, 12:48 AM | #4 |
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Related Rates: Man and Spotlight
ok so start by drawing a picture, and try and relate the distnace of the man from the light or wall to the height of the shadow - think similar triangles
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| Nov5-09, 12:56 AM | #5 |
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Yeah, that's where I run into problems.
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| Nov5-09, 02:40 AM | #6 |
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ok so what do you need a hand with?
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| Nov5-09, 10:32 AM | #7 |
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How can I go about setting up the problem? How can I go about finding an equation to solve? I understand how to solve these problems, but not how to go about setting up their equations.
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| Nov5-09, 04:05 PM | #8 |
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Think about the spot light creating a triangle and then insert the man to create a second smaller triangle. Using the numbers you have in the question, you can get your equation from that by setting the two similar triangles equal to each other - I can't remember the exact name for that, sorry. Ex. base/height of triangle one = base/height of triangle two then cross multiply and solve for your unknown that may or may not start with an s.
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| Nov7-09, 02:26 AM | #9 |
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I managed to get it. Sorry it took so long to get back. Thanks for your help!
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