How Is the MD5 Hash Algorithm Calculated?

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SUMMARY

The MD5 hash algorithm is calculated by appending a message with a '1' followed by enough '0's to make it 64 bits shy of a multiple of 512 bits, with the final 64 bits representing the original message length. The algorithm utilizes a four-word buffer and four specific functions, with the operation defined as a = b + ((a + F(b,c,d) + X[k] + T[i]) <<< s). The variable 's' is derived from a predefined sequence of shifts, specifically the middle numbers in the operation table: 7, 12, 17, and 22. Understanding these components is crucial for accurately calculating the MD5 hash value.

PREREQUISITES
  • Understanding of cryptographic hash functions
  • Familiarity with the MD5 specification (RFC 1321)
  • Basic knowledge of bitwise operations and shifts
  • Experience with hexadecimal representation of data
NEXT STEPS
  • Study the MD5 algorithm in detail through the RFC 1321 document
  • Learn about the four functions used in MD5: F, G, H, and I
  • Explore the significance of the shift values in hash calculations
  • Investigate the differences in buffer representation and their impact on calculations
USEFUL FOR

Cryptography students, software developers implementing hashing algorithms, and security professionals seeking to understand MD5 hash calculations.

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Hi. I'm studying the cryptography MD5 calculation and have some trouble I'd like to seek help with. I am trying to comprehend the MD5 memo http://www.ietf.org/rfc/rfc1321.txt" and have trouble understanding the calculation.

Here is what I comprehend so far. A message is appended with a 1 followed by enough 0s to make it 64-bits shy of multiples of 512-bit. The last 64-bits appended being the length of the original message. I know that a four-word buffer, and four functions will be used, but I am not sure how and which bits to put in place.

I'm hoping someone would be able to explain the calculation of the functions and how the hash value is derived. I'm not sure if this is possible, but say given a word, to be able to produce a hash value through calculation. Thank you.
 
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Hi, since I'm not getting any replies, I thought I might narrow down my question in hope for some answers or directions.

From ietf.org/rfc/rfc1321.txt,

Code:
The operation a = b + ((a + F(b,c,d) + X[k] + T[i]) <<< s)
I understand how to get most of the variables except s. The memo states the equation will rotate by s bit, but i do not know where is s derived from.

Code:
[ABCD  0  7  1]  [DABC  1 12  2]  [CDAB  2 17  3]  [BCDA  3 22  4]
[ABCD  4  7  5]  [DABC  5 12  6]  [CDAB  6 17  7]  [BCDA  7 22  8]
[ABCD  8  7  9]  [DABC  9 12 10]  [CDAB 10 17 11]  [BCDA 11 22 12]
[ABCD 12  7 13]  [DABC 13 12 14]  [CDAB 14 17 15]  [BCDA 15 22 16]
I also do not understand how are the numbers in these operation used. In relation to the previous question, one thing I do know is that s only uses the middle number of these operations, that is 7, 12, 17, 22.

Code:
word A: 01 23 45 67
word B: 89 ab cd ef
word C: fe dc ba 98
word D: 76 54 32 10
Another thing I'm also curious about, although not of much importance, is the representation of the buffer. Some sites reverses the register before calculation, for example word a will be 67 45 23 01. I would like to know if there is a reason behind this or just a preferred way of calculating.

I hope someone might be able to help me with these questions or point me a direction. Thank you.
 

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