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Hockey puck momentum/ collision 
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#1
Nov3009, 11:06 PM

P: 62

1. The problem statement, all variables and given/known data
A puck of mass 7 kg moving at 3 m/s strikes an identical puck that is stationery on frictionless ice. After the collision, the first puck leaves with a speed of v1 at an angle of 41.1647 degrees with respect to its original line of motion and the second puck leaves with a speed of v2 at 48.8353 degrees. 2. Relevant equations MaVa + MbVb = MaVa' + MbVb' 3. The attempt at a solution Puck along xaxis: MVa = MVa' * Cos 41.1647 + MVb' * Cos 48.8353 yaxis: 0 = MVa' * Sin 41.1647 + MVb' * Sin 48.8353 I solved for Va' and got 1.844 (rounded to 3 decimal places), but that answer is wrong. What did I do wrong? 


#2
Nov3009, 11:09 PM

P: 62

Figured it out. Calculator error.



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