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Diffraction Grating, Maxima, finding slit seperation |
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| Dec3-09, 02:54 PM | #1 |
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Diffraction Grating, Maxima, finding slit seperation
1. The problem statement, all variables and given/known data
Light of wavelength 680 nm is incident normally on a diffraction grating. Two adjacent maxima occur at angles given by sin θ = 0.2 and sin θ = 0.3, respectively. The fourth-order maxima are missing. (b) What is the smallest slit width this grating can have? 2. Relevant equations 3. The attempt at a solution What equations relate slit width to angle theta? |
| Dec3-09, 04:14 PM | #2 |
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The diffraction orders do not have to be 1 and 2. Actually they are not.
You don't need to assume their values. The information that the maxima are adjacent is enough. With your notation, that means m2=m1+1. You can find both d and m1,m2 from the equations (with the above condition). |
| Dec3-09, 05:26 PM | #3 |
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Yes, I had tried that, but it gave me values that I thought were too far from the correct answer (which I knew the value of). I've looked at all the numbers more closely, and it's just rounding preferences, is all the matter.
Thanks. |
| Dec3-09, 05:33 PM | #4 |
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Diffraction Grating, Maxima, finding slit seperation
I edited the first post, to make it about the second part of the problem, for which I cannot think of any equations.
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| Dec4-09, 08:11 AM | #5 |
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There is nothing about rounding. The diffraction orders are 1 and 2 (in the first part).
The same equation will give the minimum size of the slit. The condition is that you have only the maxima with orders 0 to 3 and nothing at 4. That means that the sin(theta) will have to be l>= 1 for order 4. |
| Dec4-09, 08:12 AM | #6 |
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There is nothing about rounding. The diffraction orders are 2 and 3 (in the first part).
The same equation will give the minimum size of the slit. The condition is that you have only the maxima with orders 0 to 3 and nothing at 4. That means that the sin(theta) will have to be l>= 1 for order 4. |
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