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Kinetic Theory Problem |
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| Jan7-10, 07:43 PM | #1 |
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Kinetic Theory Problem
1. The problem statement, all variables and given/known data
A sample of an ideal gas is at a temperature of 320 K. The rms molecular speed at this temperature is measured as 1631 m/s. Calculate the mass of a molecule of this gas 2. Relevant equations rms velocity , u = √(3RT/M ) 3. The attempt at a solution Given u = 1631 m / s Temperature , T = 320 K R = gas constant = 8.314 J/ mol . K Molar mass of the gas molecule , M = 3RT / u 2 = 3 * 10^-3 Kg / mol |
| Jan7-10, 09:41 PM | #2 |
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Recognitions:
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Right. You can convert to kg/molecule now, or you can use u=sqrt(3kT/m) instead of u=sqrt(3RT/M) and get the answer directly.
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| Jan7-10, 09:58 PM | #3 |
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so do i just multply by 6.02e23?
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