What is the change in kinetic energy of the proton?

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SUMMARY

The change in kinetic energy of a proton moving 0.1 meters in an electric field of 3 V/m is calculated using the formula KE = qEd. The correct calculation involves using the charge of the proton (1.6 x 10^-19 C) and the distance without squaring it. The correct formula application yields a change in kinetic energy of 4.8 x 10^-20 Joules, not 4.8 x 10^-25 Joules as initially calculated due to a mathematical error in squaring the distance.

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Dx
A proton moves .1m along hte direction of an electric field of magnitude 3V/m. what iss the change in kinetic energy of the proton?

I have KE = qE/d...1.6x10^-27 * 3V/m /(.1^2)= 4.8x 10^-25 but got it wrong on the test.
What did i do wrong?
Dx
 
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Originally posted by Dx
A proton moves .1m along hte direction of an electric field of magnitude 3V/m. what iss the change in kinetic energy of the proton?

I have KE = qE/d...

Note: In the formula, distance is not squared, which is correct.

1.6x10^-27 * 3V/m /(.1^2)= 4.8x 10^-25 but got it wrong on the test.
What did i do wrong?

You squared the distance, which is incorrect.
 
Ok!

Darn it! I missed that on my test, stupid math mistakes gets me all the time. Thanks Tom!
Dx :wink:
 

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