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Two Speakers - Sound Maximum and Sound Minimum Problem

by davichi
Tags: maximum, minimum, sound, speakers
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davichi
#1
Jan30-10, 05:40 PM
P: 2
Hi, I am having difficulty solving the following problem:

1. The problem statement, all variables and given/known data

Two loudspeakers 5.0 m apart are playing the same frequency. If you stand 13.0 m in front of the plane of the speakers, centered between them, you hear a sound of maximum intensity. As you walk parallel to the plane of the speakers, staying 13.0 m in front of them, you first hear a minimum of sound intensity when you are directly in front of one of the speakers.

What is the frequency of the sound? Assume a sound speed of 340 m/s.


2. Relevant equations

Sound Maximum:
L1 - L2 = n[tex]\lambda[/tex]

Sound Minimum:
L1' - L2 = (n+[tex]\frac{1}{2}[/tex])[tex]\lambda[/tex]

Frequency:
f = [tex]\frac{v}{\lambda}[/tex]

3. The attempt at a solution



Sound Maximum:
L1 - L2 = n[tex]\lambda[/tex]

L2 = 13.0 m
L1 = [tex]\sqrt{13.0^{2}+2.50^{2}}[/tex] = 13.23820229

L[tex]_{1}[/tex] - L[tex]_{2}[/tex] = n[tex]\lambda[/tex]
13.23820229 - 13 = n[tex]\lambda[/tex]
n[tex]\lambda[/tex] = 0.23820229

Sound Minimum
L1' - L2 =(n + [tex]\frac{1}{2}[/tex])[tex]\lambda[/tex]

L2 = 13.0 m
L1' = [tex]\sqrt{13.0^{2}+5.0^{2}}[/tex] = 13.92838828

Sub in n[tex]\lambda[/tex]= 0.23820229:

L1' - L2 = (n + [tex]\frac{1}{2}[/tex])[tex]\lambda[/tex]
13.92838828 - 13 = n[tex]\lambda[/tex] + [tex]\lambda[/tex]/2
[tex]\lambda[/tex]/2 = 0.92838828 - 0.23820229
[tex]\lambda[/tex] = 1.380371974

Sub in [tex]\lambda[/tex] = 1.380371974:
f = [tex]\frac{v}{\lambda}[/tex]
f = [tex]\frac{340}{1.380371974}[/tex]
f = 246.3104195 Hz

I'm not sure if my approach is wrong or if I'm interpreting the question incorrectly. Any help would be greatly appreciated!

Thanks.
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rl.bhat
#2
Jan31-10, 07:51 AM
HW Helper
P: 4,435
In the central position the two speakers are at equal distance. So the path difference is zero. In between the first and the second position, there is neither a maximum nor a minimum. So at the second position ( l1' - l2) = λ/2.
davichi
#3
Jan31-10, 08:57 AM
P: 2
Ooh.. no wonder. Thank you very much!


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