|Jan31-10, 12:51 PM||#1|
Prove that there exists an x such that x[SUP]3[/SUP] = 2
1. The problem statement, all variables and given/known data
Prove that there exists an x such that x3 = 2
2. Relevant equations
3. The attempt at a solution
I have deduced in an earlier part of the question, using the intermediate value theorem, that every monic polynomial of odd degree has a real root.
So if I consider x3 - 2 = 0, as a monic polynomial of odd degree, I know that it has a real root. Can I just say that this is the x that I am looking for? I don't feel like I've really proved it fully.
|Jan31-10, 01:00 PM||#2|
|Jan31-10, 01:01 PM||#3|
If all you have to do is prove the existence of such an x then why don't you simply find x, which isn't very difficult. Unless there is something I'm missing.
|Similar Threads for: Prove that there exists an x such that x[SUP]3[/SUP] = 2|
|Prove in any interval there exists an irrational z||Calculus & Beyond Homework||4|
|Experiment to prove that limits exists!!||Calculus||6|
|How Does One Prove One Exists?||General Discussion||128|
|Prove that torque exists||Introductory Physics Homework||1|
|I Believe In God And Can Prove God Exists!||General Discussion||16|