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Gravitational time dilation 
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#1
Feb1510, 08:41 PM

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1. The problem statement, all variables and given/known data
Calculate the difference in time after one year between a clock at Earth's surface and a clock on a satellite orbiting at 300 km above the surface 2. Relevant equations T = T0 / (1  2gR/c^2)^.5 That is, this: http://hyperphysics.phyastr.gsu.edu...grel/gtim3.gif 3. The attempt at a solution I don't understand how to use this equation to get the difference between the clock on the satellite and the clock on the surface. Do I just take the value of T with R = Earth's radius, and again with R = Earth's radius + 300 km, and take the difference? 


#2
Feb1610, 05:13 AM

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Thanks
P: 26,157

Hi Seedling!
(try using the X^{2} and X_{2} tags just above the Reply box ) T_{0} is the time on a clock "at infinity", and T_{R} is the time on a clock at radius R, so T_{R}/T_{0} is the ratio of their "speeds", and T_{R=h}/T_{R} is the ratio you want. (But remember that this formula only gives you the general relativity time dilation … there'll also be an ordinary Lorentz time dilation, in the opposite direction ). 


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