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Using the Squeeze Theorem to find Limit |
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| Feb23-10, 07:56 PM | #1 |
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Using the Squeeze Theorem to find Limit
1. The problem statement, all variables and given/known data
lim (x,y) -> (0,0) for: (x^3 - y^3) / (x2 + y2) 2. Relevant equations 3. The attempt at a solution I am checking all the possible lines to check what the limit would be if it did exist: y = mx, plug this into the equation above (x^3 - (mx)^3) / (x^2 + (mx)^2) reduces to: x(1 - m^3) / (1 + m^2) so, the limit of this when it approaches 0 would be 0 if it exists. Now how do I find out that it does exist? I was told to use the squeeze theorem, but I don't know how to find the bounds. |
| Feb23-10, 08:44 PM | #2 |
Recognitions:
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The usual approach is to use polar coordinates and write x=r*cos(theta) and y=r*sin(theta). Then if (x,y)->(0,0) r must go to zero. Bound the trig part and use the squeeze theorem.
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| Feb23-10, 08:46 PM | #3 |
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try to rewrite x^3-y^3=(x-y)(x^2+xy+y^2), and somewhere along the lines use the facts that: x^2=<x^2+y^2, y^2=<x^2+y^2, xy<x^2+y^2, to come up with an upper bound, so to speak, since your lower is 0.
EDIT: Or what Dick suggested! |
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