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Momentum + coefficient of restitution this is driving me nuts!!! |
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| Feb26-10, 12:26 PM | #1 |
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Momentum + coefficient of restitution this is driving me nuts!!!
1. The problem statement, all variables and given/known data
A Mass of 2kg travelling at 2m/s is struck by a mass of 4 kg travelling at 3m/s. If the coefficient of restitution for the two materials is 0.4 calculate their final velocities. 2. Relevant equations M1U1+M2U2=M1V1+M2V2 E=V2-V1/U2-U1 3. The attempt at a solution From what i know, the best way to do it is use both equations and create two simultaneous equations? Is this correct? i seem to end up with V2=-1.2 however im pretty sure this is wrong. any help would be great. 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution |
| Feb26-10, 01:37 PM | #2 |
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![]() Show us your full calculations, and then we'll see what went wrong, and we'll know how to help!
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| Feb26-10, 02:26 PM | #3 |
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Cheers dude :-)
first bit... 2*2+4*(-4)=2*V1+4*V2 -12=2*V1+4*V2 second bit... 0.4*2-0.4*4=v2-v1 2.4=v2-v1 so then i have -12=2*V1+4*V2 + 4.8=2V2-2V1 which gives -7.2=6V2... |
| Feb26-10, 03:14 PM | #4 |
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Momentum + coefficient of restitution this is driving me nuts!!!
Hi ar202!
![]() erm … you keep writing 4 instead of 3 …
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| Feb26-10, 04:19 PM | #5 |
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the answer is still wrong... any tips? |
| Feb26-10, 05:04 PM | #6 |
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Have you checked that your signs for V1 and V2 are the right way round in both equations?
(and btw, were they travelling in the same direction originally, or in opposite directions?) |
| Feb26-10, 05:11 PM | #7 |
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still struggling to get to those answers. |
| Feb26-10, 05:17 PM | #8 |
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relative speed before = 1, after = 0.4
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| Feb26-10, 05:25 PM | #9 |
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am i going about it the right way...? |
| Feb26-10, 05:33 PM | #10 |
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hmm … relative speed after = 0.49 … not close enough to 0.4
![]() you must be making a mistake somewhere, but without seeing the details, I can't say where. |
| Feb26-10, 05:39 PM | #11 |
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2*2+4*3=2*v1+4*v2 0.4(3-2)=v2-v1 X 2 then i've added it to the first part... so 18=6*v2 18/6=3 .... actually my answer was 3 for v2. I must be more tired than i thought :p |
| Feb26-10, 05:51 PM | #12 |
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oooh, i see it now …
the coefficient of restitution is just |u1 - u2|/|v1 - v2|
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| Feb26-10, 06:06 PM | #13 |
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the 'X2' was the simultaneous equation part...
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| Feb27-10, 03:12 AM | #14 |
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…)oh, it multiplied the whole equation! ok, then your 18 should be 16.8 |
| Feb27-10, 10:16 AM | #15 |
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ok i finally got there got it down to 6v2=15.8 15.8/6=2.53333333333 thanks for your help dude. think i made it alot harder than it should have been!!
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| Feb27-10, 11:39 AM | #16 |
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