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Need help with momentumby noname1
Tags: momentum 
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#1
Mar310, 08:55 PM

P: 129

The figure below gives an overhead view of the path taken by a 0.165 kg cue ball as it bounces from the rail of a pool table. The ball's initial speed is 2.00 m/s, and the angle θ1 = 30.0°. The bounce reverses the y component of the ball's velocity but does not alter the x component.
(b) What is the change in the ball's linear momentum in unitvector notation? (The fact that the ball rolls is irrelevant to the question.) I tried solving the one that wrong by 2*0.165*2*cos(30) = 5.72j but when i submit the answer is saying its wrong what am i doing wrong 


#2
Mar310, 10:39 PM

HW Helper
P: 3,394

Looks okay to me.



#3
Mar410, 12:18 AM

P: 62

Check your calculation, you seem to be out by an order of magnitude.
[tex]2\cdot 0.165\cdot 2\cdot \cos \left( 30 \right)=0.5716[/tex] 


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