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Find force parallel to ramp given mass and theta?

by cellfoneguy
Tags: mass, ramp, theta
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cellfoneguy
#1
Mar10-10, 09:43 PM
P: 17
1. The problem statement, all variables and given/known data
There's a block on a ramp. The block weighs 48.9 kg and the ramp's theta (the angle the ramp makes to the ground) is 45. Assumng gravity is 9.8 m/s^2, how would i find the force of the block parallell to the ramp?


2. Relevant equations
Um..maybe
F=(mu)(m)(g)
F=(mu)(normal force)
or F=ma
and all 4 kinematics equations:
D=((vi+vf)/2)*t
vf=vi+at
D=vi*t+((at^2)/2)
vf^2=vi^2+2(a)(d)

3. The attempt at a solution
So first i drew it out. the block is accelerating down the ramp, and for the FBD i found the force of gravity acting straight down (Which can be broken down into two vectors, one perpendicular to the ramp and one parallel to it), the normal force perpendicular to the slope, the acceleration downwards, and the friction backwards.
Then i'm totally baffled. Am i supposed to use the kinematics equations to find acceleration to find the block's force or soh cah toa to find his friction?
And sorry if i'm doing this wrong, this is my first post and i'm one confused little boy.
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rl.bhat
#2
Mar10-10, 09:53 PM
HW Helper
P: 4,433
Hi cellfoneguy, welcome to PF.
In the problem they have not mentioned the friction. So you need not take into account the frictional force while calculating the force on the block. The component of the weight of the block parallel to the ramp is the force on the block.
cellfoneguy
#3
Mar10-10, 09:55 PM
P: 17
So if i draw a right triangle using down (Gravity=9.8) as its hypotenuse, and the adjacent side perpendicular to the block, and the opposite side parallel to the block, maybe i can find the adjacent side? But i don't know the theta of above mentioned triangle.

rl.bhat
#4
Mar10-10, 10:00 PM
HW Helper
P: 4,433
Find force parallel to ramp given mass and theta?

the ramp's theta (the angle the ramp makes to the ground) is 45
What is this? Draw the FBD and identify the angles.
cellfoneguy
#5
Mar10-10, 10:06 PM
P: 17
here's both the given info and the FBD i drew
Attached Images
File Type: bmp fadsfasdf.bmp (263.5 KB, 21 views)
File Type: bmp aaaaaaaaaaa.bmp (263.5 KB, 18 views)
rl.bhat
#6
Mar10-10, 10:14 PM
HW Helper
P: 4,433
From the diagram can you find the angle between the gravity and the perpendicular to the ramp? Once you do that, find the parallels and the perpendicular components of the weight.
cellfoneguy
#7
Mar10-10, 10:22 PM
P: 17
uh......i'm a little confused.
so i know that if i get the angle between gravity and the ramp's perpendicular, i can find both the parallel and the perpendicular to the ramp, the two vectors of the gravity force. So i know that to find the force of the block ill need net force. To find net force, that's just the vector of the gravity force that is parallel to the ramp, right?.......
If that is right, then how do i find the theta for the gravity vector triangle?
rl.bhat
#8
Mar10-10, 10:24 PM
HW Helper
P: 4,433
Right.
cellfoneguy
#9
Mar10-10, 10:24 PM
P: 17
hmm. So then the gravity force triangle's theta is..........45?
cellfoneguy
#10
Mar10-10, 10:29 PM
P: 17
AH HA I HAVE IT NOW
thanks so much rl.bhat!


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