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Is symetry across inertial frames purely theoretical? |
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| Apr7-10, 06:42 AM | #1 |
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Is symetry across inertial frames purely theoretical?
Hi. If the twin paradox, etc, is not really a paradox because one twin experiences acceleration, then is the idea of recipricol time dilation etc due to symetry across inertial frames purely theoretical?
What I mean is that could we ever find two inertial frames moving relatively to each other in reality? At least one of them must have experienced some acceleration in order to produce the relative motion in the first place, right? Edit* I know i just explained that incorrectly. Of course we can have to inertial frames. What I mean is that because one of them must have experienced acceleration, then we will always have a "stationary" frame, and a "moving frame". |
| Apr7-10, 07:24 AM | #2 |
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The acceleration history of an object is completely irrelevant for time dilatation.
When people mention acceleration they do so to emphasize that the rocket frame is not an inertial frame. Hence you can't claim that SR predicts reciprocal time dilatation in the twin "paradox": SR predicts nothing for noninertial frames, as it is not applicable to them. Whenever you have two frames that are inertial during the experiment, there is reciprocal time dilatation, no matter what accelerations happened in the past. And in every inertial frame, you can correctly calculate proper times by applying the appropriate time dilatation (1/gamma) to each segment of the motion of the interesting object. |
| Apr7-10, 08:45 AM | #3 |
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If so, then i assume that when the rocket suddenly stops, something happens during that non-inertial period that changes the experience of time for the twins? The reason i say this is that after the stop (at the halfway point), both twins are now stationary and could agree on each other's ages by sending their ages and calculating the time it would have taken to recieve those age messages. There's no relativity of simultaneity here to nullify the paradox, so presumably the act of decelerating to a stop altered the rocket man's perception of earth time? (like it speeds up?) |
| Apr7-10, 09:44 AM | #4 |
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| Apr7-10, 04:22 PM | #5 |
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You measure the time between two events. And you measure the twin's time between two events that are simultaneous (your simultanteity) to yours. Look here for some graphics and explanation. Let's take 8 years earth time, 4 years twin time, so turnaround is after 4 years earth time / 2 years twin time. After 4 years earth time, 2 years passed for the twin. After 2 years twin time, 1 year passed for earth. See, reciprocal - if I take the twin's line of simultaneity. All that happens at turnaround is that the twins line of simultaneity shifts. That has nothing to do with the twin's perception; all events on this "line" are totally unobservable for him at that time. That's more a bookkeeping procedure, which you can verify after the experiment is over and data has been exchanged. So, for the outbound twin, the first earth year is simultaneous to his two years. For the inbound twin, it's the last earth year. All reciprocal, but somehow 6 earth years have been forgotten. The reason why - after reunification - earth is older is a very simple geometric one: earth's path through spacetime is longer than the twin's path, and proper time = path length. Just like, in ordinary euclidean geometry, two sides of a triangle are larger than the third. In relativity's spacetime, the two sides are always shorter than the straight path, but otherwise, the twin paradox is nothing but a "triangle paradox". http://www.phys.ncku.edu.tw/mirrors/...spacetime.html |
| Apr14-10, 07:37 AM | #6 |
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The sumultaneity of it al look slike this: ![]() So when the travelling twin watches the video am i right in thinking that he'd see time passing on earth very slowly on the outward journey, and then it would start to speed up and go very fast during decelleration to the point where there is no relative motion (horizontal simultaneity line) and then earth time would appear to start slowing down again as the twin had accelerated back in the opposite direction. At this point the video would be showing earth in the future (compared to the travelling twin at that point of the journey), but as earth time is now passing slowly again, the video will show rocket time running faster and the travelling twin's present catching up with that of earth. ? I'll ignore the part where the rocket stops in order to edit the video recording. |
| Apr14-10, 08:16 AM | #7 |
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You can't see things that happen simultaneously somewhere else. If you could, relativity would be absurd. What you see is plotted in the diagram above the one you cited. Information is relayed maximally at the speed of light. The red lines connect what you see with what happened - much earlier - on earth. Obviously, you can't see the future of earth at turnaround. It is a common misconception that these blue lines are somehow directly physically important. They aren't. Nothing changes for the travelling twin if the blue lines change. Nothing outside the twin's light cone at that time can possibly have anything to do with her. These blue lines are out of reach per definition. They have nothing to do with what the twin sees. |
| Apr14-10, 09:15 AM | #8 |
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![]() and run the calculations, based on distance and a constant speed of light, to transform the diagram into showing where the rocket WOULD have been when the light was emmitted from earth you'd see the second, blue lined, simultaneity diagram? If that is true then what i was trying to suggest is that simultaneous events, during turnaround, are occuring over a larger span of earth time than rocket time (longer section of the CT axis). The recording of the video, and editing it based on those calculations, was a way of observing those simultaneous events occuring in 2 frames, in one single frame. ie, the video will run for the same duration as the rocket trip, but the frames (video frames) displayed will render earth in slow motion, then fast-forward during turnaround, and back to slow motion at the end of the tape. Hence, seeing the earth in the 'calculated' future, based on a calculated rendition of the trip rather than an actual observed trip. I wonder if that makes more sense? |
| Apr14-10, 10:01 AM | #9 |
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Or, simpler, what - for the rocket - happens at a certain time anywhere in the world. The diagram itself is plotted in earth coordinates, you can directly read off where the rocket is at any instant -according to earth. There, simultaneous events are on horizontal lines. It is most importan that simultaneity means different things for different observers. |
| Apr14-10, 10:08 AM | #10 |
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