Euler-Lagrange Equations

TheDoorsOfMe

What does it mean when it says "the integral of the Lagrange equation is stationary for the path followed by the particle"?

TheDoorsOfMe

Is it just saying that the integral is a constant?

MaceLee

I would assume it means that the action [tex]s = \int Ldt[/tex] is a stationary point (i.e. a min most likely as the action is minimised in real systems).

You might want to wait for some confirmation however as I haven't studied Lagrangian mechanics in too much depth.

Cyosis

A stationary point is a point where the derivative of a function is 0. To obtain the Euler-Lagrange equations we set the variation of the action to 0.

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TheDoorsOfMe	Euler-Lagrange Equations Tweet What does it mean when it says "the integral of the Lagrange equation is stationary for the path followed by the particle"?

MaceLee	I would assume it means that the action [tex]s = \int Ldt[/tex] is a stationary point (i.e. a min most likely as the action is minimised in real systems). You might want to wait for some confirmation however as I haven't studied Lagrangian mechanics in too much depth.

Cyosis Recognitions: Homework Help	Euler-Lagrange Equations A stationary point is a point where the derivative of a function is 0. To obtain the Euler-Lagrange equations we set the variation of the action to 0.