Is pi+e Algebraic? Debunking the Mystery

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Discussion Overview

The discussion revolves around the algebraic or transcendental nature of the sum of pi and e, specifically whether pi + e is algebraic. Participants explore various mathematical implications and theorems related to transcendental numbers, including references to existing literature and proofs.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant recalls a professor mentioning the problem but does not provide a definitive answer regarding the algebraic status of pi + e.
  • Another participant cites Wolfram, suggesting that at least one of pi + e or pi * e must be transcendental, though neither has been proven to be so.
  • A different participant argues that at least one of pi + e or pi - e must be transcendental, based on the implications of algebraic numbers.
  • One participant presents a mathematical argument involving the roots of a polynomial, questioning the implications if both e + pi and e * pi were algebraic.
  • Another participant asserts that since pi and e are both transcendental, it follows that the roots of a polynomial with algebraic coefficients must also be algebraic, referencing standard algebra texts for proof.

Areas of Agreement / Disagreement

Participants express differing views on the algebraic nature of pi + e, with no consensus reached on whether it is algebraic or transcendental. Multiple competing perspectives are presented without resolution.

Contextual Notes

The discussion includes assumptions about the nature of algebraic and transcendental numbers, as well as references to mathematical proofs that are not fully detailed within the thread.

gravenewworld
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Is it algebraic? I remember my professor talking about this probelm, he just swept it under the rug. Are there any proofs that pi+e is algebraic or not?
 
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also at least one of pi+e and pi-e must be transcendental (if they were both algebraic, so would be one half their sum and difference, ie pi and e would be algebraic).
 
lets see if wolframs statement is obvious. consider (x-e)(x-pi) = x^2 - (e+pi)x + e*pi.

Now if both e+pi and e*pi were algebraic, then e and pi would be roots of an equation with algebraic coefficients, so wouldn't they both be algebraic?
 
Yes, and since pi and e are both transcendental, the result follow. That the roots of a polynomial with algebraic coefficients are algebraic follows from the fact that if F2 is and algebraic extension of F1 and F1 is an algebraic extension of F, then F2 is an algebraic extension of F (F2, F1, F fields). Proof should be in most algebra texts and isn't too difficult.
 

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