Derive StefanBoltzmann Law from Planck Distribution for blackbody radiationby omegas Tags: blackbody radiation, planck distribution, stefanboltzmann, wien displacement 

#1
Apr2710, 06:31 AM

P: 9

1. The problem statement, all variables and given/known data
Starting with the Planck distribution R([tex]\lambda[/tex],T) for blackbody radiation. (a) Derive the blackbody StefanBoltzmann law (ie total flux is proportional to T^{4}) by integrating the above expression over all wavelengths. Thus show that R(T) = (2[tex]\pi[/tex]^{5}k^{4})T^{4} / (15h^{3}c^{2} (b) Show that the maximum value of R([tex]\lambda[/tex],T) occurs for [tex]\lambda[/tex]_{m}T = 2.898 * 10^{3} mK (this is called Wien's displacement law). (c) Use Wien's displacement law to determine for the cosmic background radiation with T = 2.7 K (i) the value of [tex]\lambda[/tex]_{m} for peak intensity (ii) the energy in eV of photons at this peak intensity, and (iii) the region of the electromagnetic spectrum corresponding to the peak intesnsity. 2. Relevant equations Planck distribution for blackbody radiation: R([tex]\lambda[/tex],T) = (c/4)(8[tex]\pi[/tex]/[tex]\lambda[/tex]^{4}[(hc/[tex]\lambda[/tex])1/e^{hc/[tex]\lambda[/tex]kT}1] 3. The attempt at a solution That was a mouthful. Help please. 



#2
Apr2810, 01:11 AM

HW Helper
P: 3,309

here's how to write it in tex (click on it to see how)
[tex] R(\lamda,T) = \frac{c}{4} \frac{8 \pi}{\lambda^4} (\frac{hc}{\lambda}) (\frac{1}{e^{hc/(\lambda kT)}1}) [/tex] ps  check i got it correct now  how about simplifying and trying the intergal? 



#3
Apr2810, 02:37 AM

P: 258

(b) How do you find the maximum of a function? 


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