What is Stefan-boltzmann law: Definition and 27 Discussions

The Stefan–Boltzmann law describes the power radiated from a black body in terms of its temperature. Specifically, the Stefan–Boltzmann law states that the total energy radiated per unit surface area of a black body across all wavelengths per unit time




j






{\displaystyle j^{\star }}
(also known as the black-body radiant emittance) is directly proportional to the fourth power of the black body's thermodynamic temperature T:





j




=
σ

T

4


.


{\displaystyle j^{\star }=\sigma T^{4}.}
The constant of proportionality σ, called the Stefan–Boltzmann constant, is derived from other known physical constants. Since 2019, the value of the constant is




σ
=



2

π

5



k

4




15

c

2



h

3





=
5.670374

×

10


8




W


m


2




K


4



,


{\displaystyle \sigma ={\frac {2\pi ^{5}k^{4}}{15c^{2}h^{3}}}=5.670374\ldots \times 10^{-8}\,\mathrm {W\,m^{-2}\,K^{-4}} ,}
where k is the Boltzmann constant, h is Planck's constant, and c is the speed of light in a vacuum. The radiance from a specified angle of view (watts per square metre per steradian) is given by




L
=



j




π


=


σ
π



T

4


.


{\displaystyle L={\frac {j^{\star }}{\pi }}={\frac {\sigma }{\pi }}T^{4}.}
A body that does not absorb all incident radiation (sometimes known as a grey body) emits less total energy than a black body and is characterized by an emissivity,



ε
<
1


{\displaystyle \varepsilon <1}
:





j




=
ε
σ

T

4


.


{\displaystyle j^{\star }=\varepsilon \sigma T^{4}.}
The radiant emittance




j






{\displaystyle j^{\star }}
has dimensions of energy flux (energy per unit time per unit area), and the SI units of measure are joules per second per square metre, or equivalently, watts per square metre. The SI unit for absolute temperature T is the kelvin.



ε


{\displaystyle \varepsilon }
is the emissivity of the grey body; if it is a perfect blackbody,



ε
=
1


{\displaystyle \varepsilon =1}
. In the still more general (and realistic) case, the emissivity depends on the wavelength,



ε
=
ε
(
λ
)


{\displaystyle \varepsilon =\varepsilon (\lambda )}
.
To find the total power radiated from an object, multiply by its surface area,



A


{\displaystyle A}
:




P
=
A

j




=
A
ε
σ

T

4


.


{\displaystyle P=Aj^{\star }=A\varepsilon \sigma T^{4}.}
Wavelength- and subwavelength-scale particles, metamaterials, and other nanostructures are not subject to ray-optical limits and may be designed to exceed the Stefan–Boltzmann law.

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  1. N

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    I actually am not sure what equations are relevant here but I thought these are the relevant ones. My Approach: By Stefan-Boltzman Law, the intensity absorbed by the Earth is given as ## I = e \sigma T^4## where e is the emissivity of Earth, ##\sigma## is Stefan-Boltzman constant and T is the...
  2. jackdale

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  3. J

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  4. B

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  5. K. Doc Holiday

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  14. G

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  15. M

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  18. P

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  27. M

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