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Conservative Vector Fields |
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| Apr28-10, 11:06 AM | #1 |
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Conservative Vector Fields
If C is the curve given by r(t)=<1+3sin(t), 1+5sin^2(t), 1+5sin^3(t)>, 0≤t≤π/2 and F is the radial vector field F(x, y, z)=<x, y, z>, compute the work done by F on a particle moving along C.
Work= int (F dot dr) If F is the potential function(?), do I integrate F with respect to each variable, then substitute the values of x, y, and z in r(t)? Would this then just be dotted into 1 since d/dt sin(t) is cos(t), which is 0 at π/2? Would my answer be something like (4^2/2)+(6^2/2)+(6^2/2)? |
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| Apr28-10, 02:06 PM | #2 |
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Recognitions:
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Hint: [itex]d\textbf{r}=\textbf{r}'(t)dt[/itex]
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| Apr28-10, 06:35 PM | #3 |
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So the integral is gross?
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| Apr29-10, 01:04 AM | #4 |
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Recognitions:
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Conservative Vector Fields
No, the point of my hint is that you should differentiate your position function with respect to [itex]t[/itex], and then take the dot product with the position function and finally integrate the result. You'll have something like 6 terms to integrate, but they should all be straightforward.
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