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Conservative Vector Fields

 
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Apr28-10, 11:06 AM   #1
 

Conservative Vector Fields


If C is the curve given by r(t)=<1+3sin(t), 1+5sin^2(t), 1+5sin^3(t)>, 0≤t≤π/2 and F is the radial vector field F(x, y, z)=<x, y, z>, compute the work done by F on a particle moving along C.

Work= int (F dot dr)

If F is the potential function(?), do I integrate F with respect to each variable, then substitute the values of x, y, and z in r(t)? Would this then just be dotted into 1 since d/dt sin(t) is cos(t), which is 0 at π/2? Would my answer be something like (4^2/2)+(6^2/2)+(6^2/2)?
 
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Apr28-10, 02:06 PM   #2
 
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Hint: [itex]d\textbf{r}=\textbf{r}'(t)dt[/itex]
 
Apr28-10, 06:35 PM   #3
 
So the integral is gross?
 
Apr29-10, 01:04 AM   #4
 
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Conservative Vector Fields


No, the point of my hint is that you should differentiate your position function with respect to [itex]t[/itex], and then take the dot product with the position function and finally integrate the result. You'll have something like 6 terms to integrate, but they should all be straightforward.
 
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