## Describe geometrically the level surfaces of the functions

So the question is as titled

i) f=(x^2 +y^2 +z^2) ^1/2

if I can figure out the method I can solve the other equations but I'm not really sure where to start I know that a function f(x,y,z) of a level surface well be constant so do I just find del f ?
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 Quote by matt_crouch So the question is as titled i) f=(x^2 +y^2 +z^2) ^1/2 if I can figure out the method I can solve the other equations but I'm not really sure where to start I know that a function f(x,y,z) of a level surface well be constant so do I just find del f ?
No, this has nothing to do with the gradient. A "level surface" for any function f(x,y,z) is, as you say, the set of points (x, y, z) where f(x, y, z)= C, a constant.

Here, that gives $(x^2+ y^2+ z^2)^{1/2}= C$. What do you get if you square both sides?
 so you just square both sides so id get x2+y2+z2= C2 where C2 is just another constant is that right?
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