Can anyone tell me what is tan 50 in fractions?

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Discussion Overview

The discussion centers around the value of tan(50) and its expression in fractional form, specifically in the context of trigonometric identities and angle construction using compass and straightedge. The scope includes mathematical reasoning and theoretical exploration of trigonometric functions.

Discussion Character

  • Mathematical reasoning
  • Exploratory
  • Conceptual clarification

Main Points Raised

  • One participant asks for the value of tan(50) in fractions, specifying that the angle is in degrees.
  • Another participant questions whether "50" refers to radians or degrees.
  • A participant assumes the angle is in degrees and outlines a method to express tan(50) in terms of cos(20) using trigonometric identities and polynomial equations.
  • The same participant provides a series of steps involving trigonometric identities to derive expressions for cos(10) and cos(50) based on cos(20).
  • After clarification, the original poster confirms the angle is in degrees and inquires about the possibility of constructing a 50-degree angle using only a compass and straightedge.
  • The original poster reiterates the question about constructing a 50-degree angle, providing a link to a resource on constructible angles.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the method to express tan(50) in fractions, and the discussion remains unresolved regarding the construction of a 50-degree angle using compass and straightedge.

Contextual Notes

The discussion includes assumptions about the angle measurement and relies on specific trigonometric identities and methods that may not be universally applicable without further clarification.

benzun_1999
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Hi
can anyone tell me what is tan 50 in fractions?
-benzun
 
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What's 50?
Radians or degrees?
 
I'll assume that "50" is in degrees:
What you need is basically an expression for [tex]\cos(20)[/tex] , all the rest follow from this:

1. [tex]\cos(60)=\cos(3*20)=4\cos^{3}20-3\cos(20)[/tex]
by simple trigonometric identities.
Hence, setting [tex]y=\cos(20)[/tex] you find the required value by solving for y in the equation:
[tex]4y^{3}-3y=\frac{1}{2}[/tex] since [tex]\cos(60)=\frac{1}{2}[/tex]
You need therefore the formula for roots of 3.degree polynomials.

2. [tex]\cos(10)=\frac{1+y}{2}[/tex] by the half-angle formula.

3. [tex]\cos(50)=\cos(60)\cos(10)+\sin(60)\sqrt{1-\cos^{2}(10)}[/tex]
by the summation formula for cosine.

4. By noting [tex]\sin(50)=\sqrt{1-\cos^{2}(50)}[/tex] you may find your expression for tan(50)
 
sorry,
i ment degrees only
Thanks
Is it possible to construct 50 degrees with a compas and scale only?
-benzun
 
benzun_1999 said:
Is it possible to construct 50 degrees with a compas and scale only?
-benzun

See
http://planetmath.org/encyclopedia/ConstructibleAnglesWithIntegerValuesInDegrees.html
 
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