# Short Probability (permutation) question

by jasper10
Tags: permutation, probability
 P: 55 1. The problem statement, all variables and given/known data There is a total of 19 students sitting in a semi-cirlce. How many seating arrangements are possible, if 4 of the 19 students have to sit next to each other? 3. The attempt at a solution I'm not sure if the calculation is: 15! x 4! or 19! / 4! Thanks!
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P: 6,992
 Quote by jasper10 1. The problem statement, all variables and given/known data There is a total of 19 students sitting in a semi-cirlce. How many seating arrangements are possible, if 4 of the 19 students have to sit next to each other? 3. The attempt at a solution I'm not sure if the calculation is: 15! x 4! or 19! / 4! Thanks!
I would go with the first answer, assuming you can explain it.

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