Short Probability (permutation) question


by jasper10
Tags: permutation, probability
jasper10
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#1
May11-10, 08:11 AM
P: 55
1. The problem statement, all variables and given/known data

There is a total of 19 students sitting in a semi-cirlce. How many seating arrangements are possible, if 4 of the 19 students have to sit next to each other?


3. The attempt at a solution

I'm not sure if the calculation is:

15! x 4!

or

19! / 4!

Thanks!
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LCKurtz
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May11-10, 01:43 PM
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Quote Quote by jasper10 View Post
1. The problem statement, all variables and given/known data

There is a total of 19 students sitting in a semi-cirlce. How many seating arrangements are possible, if 4 of the 19 students have to sit next to each other?


3. The attempt at a solution

I'm not sure if the calculation is:

15! x 4!

or

19! / 4!

Thanks!
I would go with the first answer, assuming you can explain it.


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