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Short Probability (permutation) question 
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#1
May1110, 08:11 AM

P: 55

1. The problem statement, all variables and given/known data
There is a total of 19 students sitting in a semicirlce. How many seating arrangements are possible, if 4 of the 19 students have to sit next to each other? 3. The attempt at a solution I'm not sure if the calculation is: 15! x 4! or 19! / 4! Thanks! 


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