Thread Closed

Heat Removed

 
Share Thread Thread Tools
May11-10, 10:35 AM   #1
 

Heat Removed


1. The problem statement, all variables and given/known data

How much heat must be removed when 130 g of steam at 145°C is cooled and frozen into 130 g of ice at 0°C. (Take the specific heat of steam to be 2.01 kJ/kg·K.)

Answer is in kcal.

2. Relevant equations



3. The attempt at a solution

I know steam turns back into water at 100°C

Q1=C1m(deltaT)
Q1=(2010 J//kg·K)(.13kg)(418.15K-373.15K)

In the second part, instead of using the specific heat of steam, I used the specific heat of water= 4.186 joule/gram °C

Q2=C2m(deltaT)
Q2=(4.186 J/g·°C)(130g)(100°C)

I then added Q1 to Q2 and came up with an answer in Joules.
1 joule = 0.000239005736 kilocalories

But my answer is wrong. Anyone see what I missed? Probably a conversion issue.
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
PhysOrg.com
PhysOrg
science news on PhysOrg.com

>> Bird's playlist could signal mental strengths and weaknesses
>> Minus environment, patterns still emerge: Computational study tracks E. coli cells' regulatory mechanisms
>> Bacterium uses natural 'thermometer' to trigger diarrheal disease, scientists find
May11-10, 12:40 PM   #2
 
Admin
Condensation (latent heat).
Thread Closed
Thread Tools


Similar Threads for: Heat Removed
Thread Forum Replies
total heat removed from phase change Introductory Physics Homework 0
Google ad needs to be removed Forum Feedback & Announcements 10
Heat removed from a gas in a cylinder Introductory Physics Homework 1
Sudden boiling of coffee in cup after heat source removed General Physics 10