Celestial Die Hards: Escape Velocity at 1 Planck Length

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SUMMARY

The discussion centers on calculating escape velocity at 1 Planck length from an event horizon, specifically avoiding complexities introduced by rotating black holes. The participants confirm the use of the Lorentz factor, γ, defined as γ = 1/√(1 - (v/c)²), and derive an approximation for escape velocity based on the Schwarzschild radius (Rs). The final formula presented is v ≈ (1 - d/(2Rs))c, with the context that in Planck units, both G and c equal 1.

PREREQUISITES
  • Understanding of general relativity and black hole physics
  • Familiarity with the Schwarzschild radius (Rs)
  • Knowledge of Lorentz transformations and the Lorentz factor (γ)
  • Basic grasp of Planck units and their significance in theoretical physics
NEXT STEPS
  • Study the implications of escape velocity in non-rotating black holes
  • Explore the derivation and applications of the Schwarzschild metric
  • Investigate the role of Planck units in quantum gravity theories
  • Learn about the relationship between mass, energy, and escape velocity in relativistic contexts
USEFUL FOR

The discussion is beneficial for theoretical physicists, astrophysicists, and students studying general relativity and black hole mechanics, particularly those interested in the intersection of quantum mechanics and gravitational theories.

kjones000
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What is escape velocity at 1 Planck length from an event horizon? Or, if it varies with the mass, is there a simple equation for computing the escape velocity? (No rotating black holes please, they hurt my brain).
 
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kjones000 said:
What is escape velocity at 1 Planck length from an event horizon? Or, if it varies with the mass, is there a simple equation for computing the escape velocity? (No rotating black holes please, they hurt my brain).

Well, I get that
[tex]\gamma = \frac{1}{\sqrt{1-(\frac{v}{c})^2}}}=\frac{1}{\sqrt{1-\frac{2GM}{c^2r}}}[/tex]

but I could use a double-check. Assuming this is right, if we let R = Rs +d, where Rs is the schwarzxshild radius 2GM/c^2, we can approximate this as

[tex]\gamma = \sqrt{\frac{2 G M}{d c^2}} = \sqrt{\frac{R_s}{d}}[/tex]

this can be solved for v

[tex]v \approx (1 - \frac{d}{2 R_s})c[/tex]

In Planck units, G=c=1
 
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