Faraday cage ?

cragar

When this guy gets inside the Faraday cage and they hit it with like 200,000 volts from a Tesla coil , when he is inside the cage he can touch the inside and not get shocked , so basically the charge flows on the outside , is this because the electric field from all around the circle pushes the charge to the outside .?

http://www.youtube.com/watch?v=t23iXhEiQUc

poor mystic

I haven't heard many people talk about electric fields pushing!
A reasonable explanation coming from a slightly different direction is that electrons "don't like one another".
In their efforts to get as far away from one another as convenient, electrons on the inside of a conductive body get out onto the edges and even jump off into the atmosphere.

You might like the information on this link: http://www.howstuffworks.com/vdg.htm

cragar

thanks for the answer .

cragar

does the charge on a copper wire only flow on the outside of the wire ,

graphene

In electrostatics, the field inside a conductor is zero. By electrostatics, I mean an isolated conductor. If it is placed in an external field, the free electrons in the conductor would be acted upon by the field and would more towards the surface closer to the positive end, leaving behind positive atoms (or I should say ions). This separation of charges produces a field that opposes the external field. The separation takes place until the two fields cancel each other out. At this point the electron would be pulled by the the positive ions with the same force as the external force is pulling it in the opposite direction.

A copper wire, it is not an isolated conductor. It is in a circuit. The free electrons would be pulled out of the wire by the current source. As in the previous case they are not forced to settle onto the surface of an isolated conductor. So in a copper wire, electrons flow in the interior region as well.

cragar

ok thanks for the answer .