|Aug19-10, 11:52 AM||#1|
2 Resistors in Parallel versus in Series
1. The problem statement, all variables and given/known data
Two resistors when connected in series to a 110 V line use one-fourth the power
that is used when they are connected in parallel. If one resistor is 2.0 kΩ, what is the resistance of the other?
2. Relevant equations
3. The attempt at a solution
snce x= 1560
the value of another resistance is 1.56 kilo ohm
Did I do that right?
|Aug19-10, 12:35 PM||#2|
Not quite. Okay, your series formula is fine. But now you have to get the power for the resistors in series. P=I^2 R and P=V^2/R.
Now that you have the power for the series resistors, find the power for the resistors if they were in parallel. 110=i*Req again, but different Req this time.
|Aug19-10, 04:22 PM||#3|
Can I just cancel the V's out and solve like this:
R2 + 2000 = 2*(2000*R2)/(2000 + R2)
Which looks like it would require the quadratic eqn
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