Tom McCurdy
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- 1
I am very tired and am not sure if i am doing this right
[tex]convert into P=Poe^(^k^t^)[/tex]
I came up with
[tex]P=15e^(^l^n^(^1^.^5^)^t^)[/tex]
from
[tex]P=15(1.5)^t[/tex]
haha
nvm i think i got it while I was trying to figure out latex
wow--- the answer was so easy it seemed wrong
[tex]convert into P=Poe^(^k^t^)[/tex]
I came up with
[tex]P=15e^(^l^n^(^1^.^5^)^t^)[/tex]
from
[tex]P=15(1.5)^t[/tex]
haha
nvm i think i got it while I was trying to figure out latex
wow--- the answer was so easy it seemed wrong