
#1
Sep510, 01:02 AM

P: 5

1. The problem statement, all variables and given/known data
When a 70kg aluminum (density = 2.7 g/cm3) sculpture is hung from a steel wire, the fundamental frequency for transverse standing waves on the wire is 250.0 Hz. The sculpture (but not the wire) is then completely submerged in water. What is the new fundamental frequency? 2. Relevant equations f=ma fundamental frequency = (1/2L)((Tensional force/linear density)^1/2) 3. The attempt at a solution 250=(1/2L)((686N/u)^1/2)) (stuck there) 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution 



#2
Sep510, 01:38 AM

HW Helper
P: 4,442

According to the Archimedes principle, the loss of weight is equal to the weight of the displaced liquid. In the problem the liquid is the water whose density is 1 g/cm^3.
Hence when the sculpture is immersed in water, the new tension is T' = mg  mg*ρ(w)/ρ(Al) The frequency is directly proportional to the square root of the tension. Hence f/f' = sqrt(T/T') 250/f' = sqrt[1/(1  1/2.7)] Now solve for f'. 



#3
Sep510, 01:46 AM

P: 5

so in this equation, the 70kg value does not matter?
by the way, thanks a lot! :) 



#4
Sep510, 01:51 AM

HW Helper
P: 4,442

how to find fundamental frequency 



#5
Sep510, 02:03 AM

P: 5

thank you!



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