Calculus-based physics mechanics

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Homework Help Overview

The problem involves a small glass ball projected vertically in an evacuated tube, focusing on the time intervals as it passes two timers separated by a distance H. The goal is to find an expression for the acceleration due to gravity, g, in terms of H, TsubL, and TsubU.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between time intervals and velocity, with one suggesting a mathematical approach involving the initial speed and height. Another participant questions the validity of using g in the equations, expressing concern about defining it within its own context.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the use of g as an unknown in the equations, but there is no explicit consensus on the approach to take.

Contextual Notes

There is a concern regarding the constraints imposed by the teacher on the use of g in the equations, which may affect how participants approach the problem.

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Calculus-based physics...mechanics

I'm having a little trouble with this problem...

"A small glass ball is projected straight up in an evacuated tube (no air resistance) and then falls back down. During its motion it passed both an upper and a lower timer that are separted by a distance H.

Let TsubL be the time interval between the two passes across the lower timer, and TsubU be the time interval between the two passages across the upper timer.

Find an expression for the acceleration of gravity, g, in terms of H, TsubL, and TsubU.

Any help would be appreciated, but thorough explanation would be a plus. Thanks everybody.
 
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For any given vertical location the time interval between (upward and downward) crossings is [itex]\Delta t = \frac {2v}{g}[/itex]. If the initial speed is [itex]v_0[/itex] then, for a given height, [itex]v = \sqrt {v_0^2 - 2gy}[/itex] and using the information provided we have
[tex]g^2 T_L^2 = 4 \left( v_0^2 - 2g y_L \right)[/tex]
[tex]g^2 T_U^2 = 4 \left( v_0^2 - 2g y_U \right)[/tex]
Now subtract the equations and solve for g!
 
Thanks a lot Tide, but I don't think I am allowed to use acceleration due to gravity in the equations, because i am trying to define g. It's like using a word in its own definition. I don't think my teacher will let it fly.
 
I don't think that is what your teacher means. He or she is asking you to calculate the value of g which means it becomes an unknown value in your equations and you must solve for it. That is what is meant by "find an expression for."
 

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