- #1
Omid
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A locust, extending its hind legs over a distance of 4 cm, leaves the ground at a speed of 340 cm/s. Determine its acceleration, presuming it to be constant.
When I solved that, got an acceleration of 145 m/s^2 but the answer in the solutions manual is 100 m/s^2.
I used this formula :
(V_f)^2=(V_i)^2+2as
While, s=.04, V_f=3.4 m/s and V_i=0.
What's wrong ?
When I solved that, got an acceleration of 145 m/s^2 but the answer in the solutions manual is 100 m/s^2.
I used this formula :
(V_f)^2=(V_i)^2+2as
While, s=.04, V_f=3.4 m/s and V_i=0.
What's wrong ?