How to Calculate the Image Height in a Converging Mirror Problem?

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SUMMARY

The discussion focuses on calculating the height of an image formed by a converging mirror in a Grade 11 physics problem. The user provided the object height (4.8 cm), object distance (38.6 cm), and mirror curvature (30.2 cm), leading to a calculated image distance (Di) of 2.56 cm and an image height (Hi) of -0.32 cm. The negative value indicates an inverted image, but the user is advised to check their calculations as the image should be upright. The focal length (f) was correctly calculated as 15.1 cm.

PREREQUISITES
  • Understanding of mirror formulas, specifically 1/f = 1/Di + 1/Do
  • Knowledge of image formation in converging mirrors
  • Basic algebra for manipulating equations
  • Familiarity with the concept of image inversion
NEXT STEPS
  • Review the principles of image formation in concave mirrors
  • Study the effects of object distance on image characteristics
  • Learn about the significance of the sign convention in optics
  • Explore interference patterns and their mathematical descriptions
USEFUL FOR

Students studying physics, particularly those focusing on optics and mirror equations, as well as educators looking for examples of common student misconceptions in image calculations.

antiflag403
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Help would be appreciated...

Hey all,
Grade 11 physics assignment due tmrw and I am having some trouble. Any help would be appreciated. So here it is:

A candle of height 4.8 cm is placed 38.6 cm in front of a converging mirror with curvature 30.2 cm. What is the height of the image?

Heres what I have:

1/f = 1/Di + 1/ Do so... 1/15.1 = 1/Di + 1/38.6 so Di=2.56

then...

Hi/Ho = -Di/Do so... Hi/4.8 = -2.56/38.6 so Hi=-.32

where:
Ho= Height of object (candle)
Do= Distance of object
Di= Distance of image
Hi= Height of image
f=focus (which i have calculated to be 15.1)

The answer i get is -.32cm which doesn't seem right to me. Am i doing something wrong? Missing something??

As well... a totally unrelated question- When looking at interference patterns of water through 2 openings, if the second nodal line is formed at an angle of 50 degrees, will n=1 or n=1/2?

Thanks for any help!
 
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1/15.1 = 1/Di + 1/38.6 so Di=2.56 - you sure that's right?
 


Hi there,

I'm not an expert in physics, but I'll try my best to help. It looks like you have the right equations and have plugged in the values correctly. However, I noticed that you have a negative sign in your equation for Hi. This could be why you are getting a negative value for the height of the image. Remember, the negative sign indicates that the image is inverted, but in this case, the image should be upright since the object is placed in front of a converging mirror. So, you may want to double check your calculations and remove the negative sign if necessary.

Regarding your second question about interference patterns, I'm not sure about the answer. It would be best to double check with your teacher or refer to your textbook for the correct formula and values to use in this situation. I'm sorry I couldn't be of more help with that.

Good luck with your assignment! I hope you are able to figure out the correct answer for the height of the image. Keep trying and don't hesitate to ask for help if you need it. You got this!
 

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