Physics question (kinetic energy) to all that apply

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SUMMARY

The discussion centers on calculating the kinetic energy and speed of a 2.0 kg coconut falling from a height of 15 meters. The relevant formulas include kinetic energy (K = 1/2 mv²) and potential energy (PE = mgh). The conservation of mechanical energy principle is emphasized, indicating that the initial potential energy converts to kinetic energy upon impact. Both kinematics and energy conservation methods are valid for solving the problem.

PREREQUISITES
  • Understanding of kinetic energy formula (K = 1/2 mv²)
  • Knowledge of potential energy formula (PE = mgh)
  • Familiarity with conservation of mechanical energy principles
  • Basic kinematics concepts and equations
NEXT STEPS
  • Explore detailed examples of conservation of mechanical energy in physics problems
  • Learn how to apply kinematics equations to solve for final velocity
  • Investigate the relationship between potential and kinetic energy in various scenarios
  • Study the implications of gravitational acceleration on falling objects
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Students studying classical physics, educators teaching mechanics, and anyone interested in understanding energy transformations in falling objects.

airkapp
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Regarding what formula to use and how exactly is it modified to fit this problem:

A 2.0KG coconut (initially at rest) falls from the top of a coconut tree 15 m high. What is the coconut's kinetic energy when it hits the ground? What is its speed?

I went ahead and drew it out. I'm thinking I can use formulas for potential energy and kinetic. K=1/2 mv^2 and mg(z1-z2); still trying to figure out how to set it up,
thanks for reading this,
Jason
 
Last edited:
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Seems to me like it's a Conservation of Mechanical Energy problem,

Kinetic Energy is always [In Classical Physics] 1/2*m*v^2
Potential Energy here will be from gravity, mgh.

It has two points you can use, when it starts (Vo =0) and when it hits the ground (h=0).
 
Kinematics formulas will also work. You have initial velocity, acceleration, vertical distance, now find final velocity, then use that to find kinetic energy. Since this is probably in an Energy unit, though, you might want to stick to conservation of mechanical energy. Both methods work.
 

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