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Electrostatic problem |
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| Sep30-10, 09:59 AM | #1 |
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Electrostatic problem
1. The problem statement, all variables and given/known data
I'm looking at Y.K.Lim's Problems and solutions in Electromagnetism and there's one thing that's confusing me: ![]() 2. Relevant equations Where does the square in r comes from? When in the beginning it says that the electric field is: [tex]E=A\frac{e^{-br}}{r}e_r[/tex] not[tex]E=A\frac{e^{-br}}{r^2}e_r[/tex] What am I missing? And what should [tex]e_r[/tex] stand for? Charge? |
| Sep30-10, 10:52 AM | #2 |
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This E-field is not due to a single charge. It is due to a distribution of charges, so it needs not be proportional to r^2. For example, a uniformly charged plane produces uniform E-field on each side of the plane, obviously not proportional to distance^2, correct?
![]() [tex]e_r[/tex] is the unit radius vector. |
| Sep30-10, 11:06 AM | #3 |
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Ok it needs not be proportional to r^2, but why did he put it then? When taking the divergence of the field?
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| Sep30-10, 11:13 AM | #4 |
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Electrostatic problem
Oh I see. Then it seems to me that it's a typo
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| Sep30-10, 12:40 PM | #5 |
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Oh, I thought it's something new I didn't know XD
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