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Force on a Currentcarrying loop 
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#1
Oct510, 04:27 AM

P: 12

1. The problem statement, all variables and given/known data
A rectanglular loop consists of 4 turns of wire carrying a current of 2.7 A. The loop is in the xy plane, and the direction of flow of the current is shown in the figure. The loop has dimensions a = 1 cm and b = 6 cm. Consider a uniform magnetic field of strength 2.3 × 104 T in x, y, or z directions. If the uniform field of 2.3 × 104 T is along the +x axis, find the magnitude of the torque acting on the loop and the total force on side a and b. Diagram: http://uploadpic.org/viewpic.php?img=100601 2. Relevant equations t = NIABsin(theta) B=unI (n= # of turns, u = 4 * 3.14 * E7) F=ILBsin(theta) 3. The attempt at a solution I found torque using the above equation, and it was 1.49E6 Fb is simply 0 because it is parallel to the magnetic field but I have NO IDEA how to solve for Fa. I tried using F=ILBsin(theta), (=2.7*.1m*2.3E4) and it rejects my answer. I also tried =2.7*.1m*2.3E4*2. Please help me find Fa? 


#2
Oct510, 05:26 AM

HW Helper
P: 4,433

you have not used the number of turns in the solution.



#3
Oct510, 05:29 AM

P: 12

I did use it to find torque, but did not use it when finding force. how do I use it in the solution? please tell me. 


#4
Oct510, 05:35 AM

HW Helper
P: 4,433

Force on a Currentcarrying loop
It will be 4 times the force on each turn.



#5
Oct510, 05:40 AM

P: 12




#6
Oct510, 05:56 AM

HW Helper
P: 4,433

What is torque? FXb. In that calculation you have used no. of terns to calculate the force. Same thing is true for Fa. 


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