Solve Momentum Question: Mass 33 kg, Velocity 4.0 m/s

  • Thread starter Thread starter antiflag403
  • Start date Start date
  • Tags Tags
    Momentum
Click For Summary

Homework Help Overview

The problem involves a child of mass 33 kg jumping off a wagon with a mass of 7.2 kg, and the child's velocity after jumping is given as 4.0 m/s to the right. The objective is to determine the velocity of the wagon after the child jumps off, with considerations of momentum conservation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial conditions of the wagon's motion, questioning whether it is moving before the child jumps. Some suggest assuming the wagon is stationary, while others explore the implications of different initial velocities.

Discussion Status

There is an ongoing exploration of the assumptions regarding the initial velocity of the wagon. Some participants provide guidance on applying momentum conservation principles, while others express confusion about the setup and calculations involved.

Contextual Notes

Participants note the lack of explicit information regarding the initial velocity of the wagon, which affects their calculations and assumptions. The discussion reflects uncertainty about how to proceed without this information.

antiflag403
Messages
45
Reaction score
0
Hey everyone!
I am having some trouble with this problem. I would appreciate any help/advice/hints.

A child of mass 33 kg jumps off of a wagon. After jumping, the child's velocity is 4.0 m/s
. If the mass of the wagon is 7.2 kg, determine the velocity of the wagon after the child jumps off.

All I have figured is that the childs momentum is 132 Kgm/s right.
I am confused as to how to get the velocity of the wagon now. I do not have enough info to use Momentum= Mass X Velocity.

Any help would be appreciated.​
 
Physics news on Phys.org
Just before the child jumps off the wagon, do they have any velocity?
 
I think you mean, is the wagon moving with the child in it?? and if so, i do not know. What i have here is what is given in the question. this is what is messing me up too. I am not sure if i should assume the wagons V is 0.
 
Assume that the wagon is not moving. You know the momentum before (0) and you have the momentum of the child. What must be the momentum of the wagon after the child jumps if momentum is conserved?
 
Yeah, well if the wagon just starts moving as the child jumps off, you do:

momentum initial = momentum final
(33kg+7.2Kg)(0) = (33Kg)(4)m/s) + (7.2Kg)(x)

Then, just solve for x
 
the momentum is therefore equal to the momentum of the child?
so...
132=7.2(v)
v= 18.3 m/s
Is that correct??
thanks for the help guys
 
Hi,

If you assume the wagon has a velocioty to start with that is unknown, the proceed like this. (to the right is the positive direction)

The momentum after is M(wagon) *V(wagon after) plus 132.

This is equal to m(wagon plus child)*v(wagon and child before)

You can then solve for V as a function of v.

If v=0, Then V=132/7.2 to the left.

juju
 
Last edited:
ok I'm not sure if i understand. so you are assuming V(Wagon) before is 0 so v=132/7.2. (this is what i was doing) what if you assumed V(wagon) to be 1m/s. can you make an equation for this instance??
 
Last edited:
I guess you must assume the initial velocity of the wagon and the child (before he jumps) is zero, unless it is stated in the problem. You can't just asssume the initial velocity is a random number.
 
  • #10
HI,

The general equation works out to be as follows.

V=(40.2*v-132)/7.2

where V=vleocity of the wagon after the child jumps off

and v=the velocity of the child and the wagon before the child jumps off.

This equation results from equating the total momentum of the wagon and the child before to the total momentum of the wagon and child after.

The velocities are considered positive to the right and negative to the left.

juju
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
2K
Replies
18
Views
8K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
335
Views
18K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K