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What exactly is the Ultraviolet Catastrophe? |
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| Oct18-10, 11:43 AM | #1 |
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What exactly is the Ultraviolet Catastrophe?
I tried looking it up, but I just don't get it. Something about intensity going to infinite(?)
What exactly was the original theory and how does the "quantized" theory account for stuff? I'm sorry if this is a dumb question :/ |
| Oct18-10, 11:57 AM | #2 |
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The problem was that classical theory gave an infinite (silly) answer for black body radiation....quantum theory via Planck solved the riddle....
This is a good explanation... http://en.wikipedia.org/wiki/Ultraviolet_catastrophe |
| Aug6-12, 04:03 PM | #3 |
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the intensity is decreasing for higher frequency. see this explanation
http://www.youtube.com/watch?v=4o9mCTXE-UQ |
| Aug7-12, 09:47 AM | #4 |
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What exactly is the Ultraviolet Catastrophe? |
| Aug7-12, 10:50 AM | #5 |
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| Aug7-12, 11:15 AM | #6 |
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In the UTube movie, they were showing a progressive wave with the string (referring to light ) and relating the length of the string that they unwound off some pins to the energy of the wave. That passage made no sense to me as the string was no more than a graph of displacement (possibly?) with distance. How does that relate to energy? It was so bad that I really couldn't go along with any more of it. The Wiki link was fine btw. |
| Aug7-12, 03:16 PM | #7 |
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In classical theory energy can be shared amongst waves of all frequencies. If a box contains electromagnetic waves there will be more waves in a range of frequencies at the high frequency end than at the lower frequency end and this suggests that more of the energy will be at the high frequency end (ultra violet is high frequency waves).
Plancks theory states that energy can only be emitted or absorbed in packets called photons. The energy of a photon is proportional to the frequency. ALSO the probability of getting a high energy photon (compared to the average energy) is lower. Just like the probability of finding a very high energy molecule in a gas at a certain temperature (average energy). This accounts for the shape of the black body spectrum just like the Boltzmann distribution accounts for speed distribution of molecules. |
| Aug7-12, 04:51 PM | #8 |
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| Aug7-12, 04:53 PM | #9 |
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Zero out of ten for production values and not much more for content, I think!
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