Will Applying Brakes Prevent Sue's Collision with the Van?

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SUMMARY

Sue, driving at 30 m/s, observes a van 155 m ahead moving at 5 m/s. Upon applying brakes with an acceleration of -2.00 m/s², calculations show that it will take her 13.63 seconds to stop. During this time, the van will travel 68.15 m, while Sue will cover 408.9 m, confirming that no collision will occur. This analysis underscores the importance of understanding acceleration and distance in collision scenarios.

PREREQUISITES
  • Understanding of kinematic equations, specifically d = vi * t + (1/2) * a * t²
  • Knowledge of acceleration concepts, including negative acceleration
  • Familiarity with the quadratic formula for solving equations
  • Basic principles of relative motion between two objects
NEXT STEPS
  • Study kinematic equations in detail, focusing on their applications in collision analysis
  • Learn about the implications of negative acceleration in real-world driving scenarios
  • Explore the use of the quadratic formula in physics problems
  • Research safe following distances and braking distances for various vehicle types
USEFUL FOR

Drivers, automotive safety analysts, physics students, and anyone interested in understanding the dynamics of vehicle motion and collision avoidance.

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Sue is driving at 30m/s, she observes a slow moving van 155m ahead traveling at 5m/s. If Sue applies her breaks and accelerates at -2.00m/s^2 will there be a collision?

How should I start to tackle this question?
 
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To begin, it is important to understand the concept of acceleration and how it affects motion. Acceleration is the rate of change of an object's velocity over time, and it can either be positive (speeding up) or negative (slowing down). In this scenario, Sue is driving at a constant velocity of 30m/s, meaning she is not accelerating. However, when she applies her brakes, she will experience a negative acceleration of -2.00m/s^2.

Next, we need to determine the distance and time it will take for Sue to come to a stop. Using the equation d = vi * t + (1/2) * a * t^2, where d is the distance, vi is the initial velocity, a is the acceleration, and t is the time, we can plug in the values given in the scenario. Sue's initial velocity is 30m/s, and her acceleration is -2.00m/s^2. We do not know the time, so we can leave it as t. The distance, d, is the sum of the distance between Sue and the van (155m) and the distance it takes for Sue to come to a stop. Therefore, the equation becomes 155m = 30m/s * t + (1/2) * (-2.00m/s^2) * t^2.

To solve for t, we can rearrange the equation to t^2 - 15t + 155 = 0. Using the quadratic formula, we find that t = 13.63 seconds. This means it will take Sue 13.63 seconds to come to a stop after applying her brakes.

Now, we can determine if there will be a collision. In that 13.63 seconds, the van will have traveled a distance of (5m/s * 13.63s) = 68.15m. This means that when Sue comes to a stop, she will have traveled a distance of (30m/s * 13.63s) = 408.9m. Since the van will only be 68.15m ahead of Sue, there will not be a collision.

In conclusion, by using the equation for distance and understanding the concept of acceleration, we can determine that there will not be a collision between Sue and the slow-moving van. However, it is important for Sue to always maintain a safe distance from other vehicles and to
 

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