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Spin of the photon 
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#1
Oct2910, 03:49 PM

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hi,
if i understand relativity well, in our frame of reference a photon does not change(infinite time dilation). then if we try mathematically to describe its spin as an intrinsic angular momentum, then there should be no observed angular momentum in our frame of reference because this angular momentum would be at the event horizon and time stops at the event horizon in our reference frame. is it correct? thank you for your reply! 


#2
Oct2910, 04:46 PM

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What event horizon? Are you talking about Hawking radiation?



#3
Oct2910, 05:24 PM

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See any of the zillion threads about how a photon doesn't have a "frame of reference" in the usual sense.
This doesn't prevent photons from having an affine parameterization. There's a handful of threads that discuss this, too, though not as many as the first. A photon doesn't experience time as its worldline is null, but you can still order events along it's worldline in a sequence by an "affine parameter", even though it's a null worldline (and usually a null geodesic worldline). 


#4
Oct2910, 11:07 PM

P: 60

Spin of the photon



#5
Oct2910, 11:11 PM

P: 60

by the way how does spin transform under Lorentz transformations? thank you for your reply! 


#6
Oct3010, 07:12 AM

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#7
Oct3010, 10:20 AM

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PF Gold
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#8
Oct3010, 11:43 AM

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#9
Oct3010, 12:02 PM

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PF Gold
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A similar confusion can occur when you talk about an ordinary planepolarized EM wave. If you believed that something was moving through space along a sinusoidal path, then its velocity would be >c. 


#10
Oct3010, 03:02 PM

P: 60

ok, so if i understand well, even if spin causes polarization, polarization is not the rotation described by spin, and nothing describes the spin rotation physically?



#11
Oct3110, 05:37 AM

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#12
Oct3110, 08:38 AM

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Some good insights into spin here:
http://en.wikipedia.org/wiki/Particle_spin Spin effects show themselves as in Pauli exclusion and polarization (described already) and as a degree of particle freedom... 


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