Limit and Derivative Problems with Infinity: Can Someone Explain?

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SUMMARY

This discussion focuses on solving limit problems involving infinity and derivatives. The specific limits addressed include: lim as n approaches infinity of 1/[1-(n/(n-1))], lim as n approaches infinity of (n-1)/[n-(1/n)], lim as n approaches infinity of n * sin(1/n), and lim as n approaches infinity of (1/n)-(1/(n+1)). Additionally, the discussion explores the limit as x approaches 0+ of {[1+(x/2)]^(2/x)}^(1/2) equating to e^(1/2). Key insights include the simplification of terms and the behavior of functions as they approach their limits.

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Would some one please show me how to do these problems below.
Thanks so much
1) lim of n as n approaches to infinity 1/[1-(n/(n-1))]
2) lim of n as n approaches to infinity (n-1)/[n-(1/n)]
3) lim of n as n approaches to infinity n * sin (1/n)
4) lim of n as n approaches to infinity (1/n)-(1/(n+1))

****Would u please also explain this to me:
Y does lim of x as x approaches to 0+ {[1+(x/2)]^(2/x)}^(1/2) = e^(1/2)?
I don't understand y they r equal??
 
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Would some one please show me how to do these problems below.
Thanks so much
1) lim of n as n approaches to infinity 1/[1-(n/(n-1))]
2) lim of n as n approaches to infinity (n-1)/[n-(1/n)]
3) lim of n as n approaches to infinity n * sin (1/n)
4) lim of n as n approaches to infinity (1/n)-(1/(n+1))

****Would u please also explain this to me:
Y does lim of x as x approaches to 0+ {[1+(x/2)]^(2/x)}^(1/2) = e^(1/2)?
I don't understand y they r equal??
 
1) lim of n as n approaches to infinity 1/[1-(n/(n-1))]

look at the n/n-1 part first.

Times both the top and the bottom by 1/n. That gives you 1/(1-1/n) The 1/n term goes to zero, so this part = 1

that leaves you with lim as x goes to 1 of 1/1-x, which is means the denominator goes to zero, so the equation goes to infinity.

Why don't you post what part you are stuck on with the rest?
 

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