- #1
Casio
- 9
- 0
e^(-Nx^2)cos(Mx) dx = ? (M,N are const)
Please help. Thanks.
Please help. Thanks.
Interate the below fucntion from 0 to infinite please
- Thread starter Casio
- Start date
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- Tags
- Infinite
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Homework Help Overview
The discussion revolves around the integral of the function e^(-Nx^2)cos(Mx) with respect to x, where M and N are constants. Participants are exploring the limits of integration and the implications of those limits on the outcome of the integral.
Discussion Character
- Exploratory, Assumption checking
Approaches and Questions Raised
- Some participants question whether the limits of integration should be from negative infinity to positive infinity, suggesting that this could affect the nature of the resulting function. Others express uncertainty about the results obtained after extensive calculations.
Discussion Status
The discussion is ongoing, with participants sharing their thoughts on the limits of integration and the resulting complexity of the integral. There is mention of a specific result obtained by one participant, but no consensus has been reached regarding the correct approach or interpretation.
Contextual Notes
One participant indicates that they have spent considerable time on the problem, suggesting that there may be constraints or challenges in arriving at a solution. There is also a reference to the complexity of the error function in relation to the limits of integration.
- #2
Casio
- 9
- 0
I won't change anything in the above post before reading your posts 
- #3
Tide
Science Advisor
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Are you sure the limits aren't from negative infinity to positive infinity? Otherwise, you will end up with a complex error function (real part).
- #4
Casio
- 9
- 0
I am sure, I check carefully, I aldready tried, its over 6 and a half pages but unable to get the valeu, you can check it yourself or you want to see my part ?Tide said:
- #5
Tide
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This is what I get:
[tex]Re \sqrt {\frac {\pi}{4m}} e^{i \frac {n^2}{4m}} \left( 1 + erf \left( \frac {im}{2\sqrt m} \right) \right)[/tex]
[tex]Re \sqrt {\frac {\pi}{4m}} e^{i \frac {n^2}{4m}} \left( 1 + erf \left( \frac {im}{2\sqrt m} \right) \right)[/tex]