
#1
Sep2604, 12:35 AM

P: 39

hi, could smne pls give me an idea of how to deal with this problem?
Suppose that f(0) = 0 and that f'(0) =1 , calculate f(f(f(x))) at point x=0 thanks a lot, any hint at all would b helpful, as i completely clueless. 


#2
Sep2604, 12:47 AM

P: n/a

if f(0) = 0 then f(f(0)) = f(0) = 0.. it's recursive. I am not sure why you would need f'(x) to solve nothing to do with derivatives. Are you sure you typed the question correctly?




#3
Sep2604, 01:06 AM

P: 39

here it is again:
f(0) = 0 and f'(0) = 1 calculate the derivative of f(f(f(x))) at point x=0 that's the exact question. thanks for the help on the second question 


#4
Sep2604, 01:11 AM

P: n/a

derivatives
Oh I see calculate the DERIVATIVE of f(f(f(0)))
First lets set g(x) = f(f(x)) g'(x) is therefore f'(f(x))*f'(x) Derivative f(g(x)) after substitution is f'(g(x))*g'(x) = f'(f(f(0)))*f'(f(0))*f'(0) What a mouthful. If I were to venture a wild crazy guess I'd say that simplifies to 1. 



#5
Sep2604, 01:31 AM

P: 39

oh great! i just worked it out, it did come to 1. thanks a lot.
can u give a further hint on the other question, i'm still a bit confused there. thanks again, marvellous! 


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