| New Reply |
Double inner product of derivative of a 2nd order tensor with another 2ndorder tensor |
Share Thread | Thread Tools |
| Nov21-10, 01:09 PM | #1 |
|
|
Double inner product of derivative of a 2nd order tensor with another 2ndorder tensor
Some one please help me how to prove the following:
[tex]\dot{A}:B + A:\dot{B}=A^{\nabla J}:B+A:B^{\nabla J}[/tex] A and B are II order tensors and : represents the inner product. |
| Nov21-10, 01:25 PM | #2 |
|
|
How do I prove the following:
[tex]\dot{A}:B + A:\dot{B}=A^{\nabla J}:B+A:B^{\nabla J}[/tex] |
| Nov21-10, 03:31 PM | #3 |
|
|
Where did you get this notation from? What is your dot? What is your J? What do you mean by "inner product", for what kind of tensors? Any reference to some place where your original notation is defined?
|
| Nov21-10, 03:55 PM | #4 |
|
|
Double inner product of derivative of a 2nd order tensor with another 2ndorder tensor
The dot represents material time derivative. A and B are second order tensors, eg Stress.
I myself am not clear what [tex]\nabla J[/tex] means here. However, I guess it represents divergence. This was as a homework question for a Continuum Mechanics course. I have not got any luck trying to understand or prove this expression. Any insight will be greatly appreciated. |
| New Reply |
| Thread Tools | |
Similar Threads for: Double inner product of derivative of a 2nd order tensor with another 2ndorder tensor
|
||||
| Thread | Forum | Replies | ||
| Riemann Curvature Tensor and working out independent components of a tensor generally | Calculus & Beyond Homework | 2 | ||
| Rank 3 tensor created by taking the derivative of electromagnetic field tensor | Advanced Physics Homework | 1 | ||
| The Tensor Product | Differential Geometry | 14 | ||
| Tensor product | Calculus & Beyond Homework | 0 | ||
| Tensor Product | Differential Geometry | 3 | ||