Math Test Question: Guess the Answer

  • Thread starter Thread starter UrbanXrisis
  • Start date Start date
  • Tags Tags
    Test
Click For Summary
SUMMARY

The discussion centers on the properties of mathematical functions, specifically focusing on the concepts of one-to-one functions and symmetry about the origin. Participants analyze the function values provided, concluding that if F(-1) = 2 and F(2) = 2, then F is not one-to-one. Additionally, the discussion highlights the characteristics of odd functions, exemplified by f(x) = x^3, which demonstrates symmetry about the origin. The analysis of functions G and H further illustrates these concepts, confirming that G is not one-to-one and H is symmetric about the origin based on the given values.

PREREQUISITES
  • Understanding of one-to-one functions
  • Familiarity with odd functions and their properties
  • Basic knowledge of function notation and evaluation
  • Concept of symmetry in mathematical functions
NEXT STEPS
  • Study the definition and examples of one-to-one functions
  • Learn about odd and even functions in depth
  • Explore function symmetry and its implications in graphing
  • Investigate the implications of function values on their properties
USEFUL FOR

Students, educators, and anyone interested in understanding the properties of mathematical functions, particularly in the context of higher education mathematics.

Mathematics news on Phys.org
Like Jasonrox I don't know what you mean I would advise you making
it very clear exactly what the question says because it does not look
anything like any other question I have seen teaching at uni or school.

is F(-2) = 1, F(-1) =-2 ,F(0)=0,F(1) =-1. F(2)=2 ?

If you have something like F(x)=F(y) when x is not y
then the function is not one to one.
eg if F(-1) = 2 and F(2)=2 then the function F is not one to one.

the comment about odd functions is a common question I have taught at uni and school if f(x) = x^3 then f(-x) = -f(x) so x^3 is odd and symmetrical about the origin.
 
Last edited:
A function is NOT "one-to-one" if f(x)= f(y) for different x and y.
A function is "symmetric about the origin" if f(-x)= -f(x) (A line drawn through the points (x, f(x)) and (-x,-f(x)) has the origin at its center).

I'm not crazy about problems where you are asked to decide something like that given only some of the values (strictly speaking that's impossible!) but assuming that the values given are sufficient, I note that G(-2)= 3= G(2) so G is NOT one to one. Also, H(-2)= 1 and H(2)= -1, H(-1)= -3 and H(1)= 3 so, at least for the values shown, H is symmetric about the origin.
 

Similar threads

  • · Replies 47 ·
2
Replies
47
Views
9K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
754
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 24 ·
Replies
24
Views
9K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K