Finding Fourier Transform for x(t): A Math Student's Query

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Homework Help Overview

The discussion revolves around finding the Fourier transform of a piecewise function defined using the Heaviside step function, specifically x(t) = θ(t-t1) - θ(t-t2), with the condition that t2 > t1. Participants express concerns about their lack of exposure to Fourier transforms in their coursework.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to set up the integral for the Fourier transform but expresses uncertainty due to their limited background in the relevant mathematical concepts. Some participants suggest simplifying the integral by recognizing the behavior of the function within specific intervals.

Discussion Status

Participants are actively engaging with the problem, with one confirming their understanding of the function's behavior and how it simplifies the integral. There is a supportive exchange, but no explicit consensus on the overall approach to the Fourier transform has been reached.

Contextual Notes

The original poster notes that they have not learned about convolution or Fourier transforms in their math class, indicating a potential gap in their background knowledge relevant to the problem.

cepheid
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In an assignment, I've been given a function:

[tex]x(t) = \theta(t-t_1) - \theta(t-t_2)[/tex]

Assume [itex]t_2 > t_1[/itex]

and we are asked to find the Fourier transform. So I wrote down:

[tex]x(\omega) = \int_{-\infty}^{\infty}{e^{-i\omega t} [\theta(t-t_1) - \theta(t-t_2)] dt}[/tex]

I know that the function given is the heaviside step function. Its derivative is the dirac delta function, and it is itself the derivative of the ramp function. But I just found this stuff out by looking online. We've learned neither convolution nor Fourier transform in math class, yet somehow this physics prof expects us to do it. Can someone at least point me in the right direction?

Thanks.
 
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Your integrand is zero everywhere except in the interval from t1 to t2 - integrate it directly!
 
Ok, I feel stupid! :smile:

Just to see if I'm understanding you correctly, x(t) can be broken down as follows:

x(t) = 0 - 0 for t < t1

x(t) = 1 - 0 for t1 < t < t2

x(t) = 1 - 1 for t > t2

This is just the first statement in your post.

So the integral reduces to:

[tex]x(\omega) = \int_{t_1}^{t_2}{e^{-i\omega t}dt}[/tex]

Am I right? The help was much appreciated!
 
You got it - WTG!
 

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