Sequare box reactor

matt222

Iam trying to work out question related to sequare box, my question is what the flux general equation for the sequare box?

I work it out and found it is

flux=Acos(pi*x/a)cos(pi*y/a)cos(pi*z/a)

where a is side lenght, am i right

Astronuc

Yes - with -a/2 < x < a/2, and similarly for y and z.

This assumes zero flux boundary condition at the edges (flux(-a/2) = flux(a/2) = 0), and max flux at flux(x,y,z) = flux(0,0,0) = A and even symmetry.

Flux is then described by 3 independent functions X, Y, Z which are described by X'' + (pi/a)²X = 0 and X(0) = Y(0) = Z(0) = A^1/3

matt222

do you agree with me when we use neutron diffusion equation, that the general solution will be

flux(x,y,z)=S/(D[3pi^2/a^2+1/L^2])


and what about if we have no source and steady state? How the general equation going to be, should we take it as

flux(x,y,z)=Aexp(-x/a)+Bexp(x/a)