Projectile Motion angled downwards

Click For Summary

Homework Help Overview

The discussion revolves around a homework problem related to projectile motion, specifically involving a projectile launched downward at an angle. The scenario includes a gun aimed at 40 degrees below the horizontal, with a given muzzle velocity and height above the ground. Participants are exploring the implications of this downward angle on the projectile's motion and calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate various parameters of the projectile's motion, including initial and final velocities, time to hit the ground, and horizontal distance traveled. They express uncertainty about the nature of the motion and the correctness of their calculations, particularly regarding the final vertical velocity.

Discussion Status

Some participants have provided feedback on the calculations, particularly noting errors in the vertical velocity component. There is an ongoing exploration of the mathematical relationships involved, with participants questioning the assumptions about the nature of the projectile's path and its parabolic characteristics.

Contextual Notes

The original poster mentions a list of questions related to the problem, indicating a structured assignment. They also express concern about making errors that could compound in their calculations.

NYmike
Messages
8
Reaction score
0
Hello all. I am currently taking an AP Physics class in high school. My teacher has given us a homework assignment involving projectile motion, however, it is different than anything else we have done. Usually, the angle is upward, or directly horizontal...This question is downward. My textbook does not offer any examples, so I am unsure of where to go for help.

A gun is pointed down at an angle 40 degress below the horizontal. The muzzle velocity is 350 m/s and the bullets mass is 30 g. The gun is 600 m above the ground. Calculate how long it takes to hit the ground, the horizontal distance traveled, the vertical velocity as it hits the ground, ...

The mass is useless, but it's given. There is a list of 10 or so questions, but I just need help getting started. I don't want 1 error to snowball.

In a normal parabola, the final vertical velocity is the negative value of the inital vertical velocity. However...this wouldn't be a normal parabola, right? Because it's just getting shot diagonally in a downward motion.

VERTICAL:

vi = 224.98 m/s
vf = -224.98 m/s
t =
d = -600 m
a = -9.8 m/s^2 (neglect air resistance)

HORIZONTAL:

vi = 268.11 m/s
vf = 268.11 m/s
t =
d =
a = 0 m/s^2


Would that be correct for the givens? I took sin and cos of 40. I am just not sure if the final vertical velocity is correct, because I don't think it would be a parabola.

Sorry for writing so much, and thank you for any help that you can provide =D
 
Physics news on Phys.org
Your horizontal information is correct (I did not check your arithmetic).But you vertical information is not. The initial velocity should be negative, you need to compute the final velocity with the information given.
 
Integral said:
Your horizontal information is correct (I did not check your arithmetic).But you vertical information is not. The initial velocity should be negative, you need to compute the final velocity with the information given.

pssh...I was thikning way too into it...thanks for your help.

I used the formula vf^2 = vi^2 + 2ad

Mathematically the answer turns out to be a positive number...Since it is still in the downward direction however, i should make it negative, correct?

EDIT: And thanks for moving the thread. Sry




What is the mathematical term for the path that the bullet takes? Projectile motion is always parabolic, however I am not able to see how that can be so with this problem...
 
Last edited:
If you were to graph it (distance vs time), youd see why it is parabolic. If the bullet was shot at 0 degrees (horizontally), youd see half the parabola. You would see half the parabolic curve because at this point the vertical velocity was 0 (which is also true when a projectile reaches the maximum height in its flight). In that case, its as if you are only seeing half the projectiles motion. A similar situation occurs in this example. However, the projectile does not start at the maximum height, it begins on its way back downwards. Thats why you would only see a certain portion of the parabola. In each situation, the projectile follows a parabolic curve. However, in the last 2 situations, it only doesn't do so for the entire curve. Does that make any sense?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
40
Views
4K
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
18
Views
2K
  • · Replies 2 ·
Replies
2
Views
876
Replies
16
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K