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V* ≠ {0} |
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| Jan4-11, 11:58 AM | #1 |
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V* ≠ {0}
Is there an easy way to see that if V is a (non-empty and non-trivial) normed space, there exists a non-zero continuous linear functional on V? To put it another way: Is there an easy way to see that V*≠{0}?. Do we have to use the Hahn-Banach theorem for this?
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| Jan4-11, 01:11 PM | #2 |
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If V is finite dimensional, then V* is always nonempty.
But for infinite-dimensional space, you will have to use Hahn-Banach. This theorem will give you a nontrivial bounded functional. |
| Jan4-11, 01:25 PM | #3 |
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Sorry if this is nonsense, it's been a while, but isn't the norm continuous by definition?
I.e. isn't [tex]|| \cdot || : V \to \mathbb{R}, f \mapsto ||f||[/tex] a linear functional on V? Clearly it is non-zero, because ||f|| = 0 iff f = 0. |
| Jan4-11, 01:35 PM | #4 |
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V* ≠ {0}
Norm is not linear because for [itex]v\neq 0[/itex]
[tex]||-v||\neq -||v||[/tex] |
| Jan4-11, 02:31 PM | #5 |
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Good point.
Never mind I said something. * whistles and shuffles away innocently * |
| Jan4-11, 03:05 PM | #6 |
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Thanks, that's what I thought. I got a little confused by the fact that immediately before stating the Hahn-Banach theorem, the book suggested that I think about why V*≠{0}. It's hard to know if I'm supposed to try and succeed, or try and fail just to see that we need a fancy theorem.
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